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©2024 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
2
2
(
x
+
)
=
1
5
(2)
1
2
(
x
−
)
=
1
2
(3)
3
2
9
(
x
+
)
=
4
49
(4)
1
2
(
x
−
)
=
1
2
(5)
2
2
1
(
x
+
)
=
3
4
(6)
2
1
(
x
−
1
)
=
4
(7)
5
2
4
(
x
+
)
−
=
0
4
49
(8)
2
2
(
x
−
)
=
1
3
(9)
2
1
(
x
+
1
)
−
=
0
4
(10)
3
2
1
(
x
+
)
=
2
4
©2024 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
2
(
x
+
)
5
=
1
2
x
+
5
=
±
1
x
2
=
−
±
1
5
x
3
7
=
,
−
5
5
(2)
1
2
(
x
−
)
2
=
1
1
x
−
2
=
±
1
x
1
=
±
1
2
x
3
1
=
,
−
2
2
(3)
3
2
(
x
+
)
4
9
=
49
3
x
+
4
3
=
±
7
x
3
3
=
−
±
4
7
x
9
33
=
−
,
−
28
28
(4)
1
2
(
x
−
)
2
=
1
1
x
−
2
=
±
1
x
1
=
±
1
2
x
3
1
=
,
−
2
2
(5)
2
2
(
x
+
)
3
1
=
4
2
x
+
3
1
=
±
2
x
2
1
=
−
±
3
2
x
1
7
=
−
,
−
6
6
(6)
2
(
x
−
1
)
1
=
4
x
−
1
1
=
±
2
x
1
=
1
±
2
x
3
1
=
,
2
2
(7)
5
2
4
(
x
+
)
−
4
49
=
0
5
x
+
4
2
=
±
7
x
5
2
=
−
±
4
7
x
27
43
=
−
,
−
28
28
(8)
2
2
(
x
−
)
3
=
1
2
x
−
3
=
±
1
x
2
=
±
1
3
x
5
1
=
,
−
3
3
(9)
2
1
(
x
+
1
)
−
4
=
0
x
+
1
1
=
±
2
x
1
=
−
1
±
2
x
1
3
=
−
,
−
2
2
(10)
3
2
(
x
+
)
2
1
=
4
3
x
+
2
1
=
±
2
x
3
1
=
−
±
2
2
x
=
−1
,
−2