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©2025 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
2
(
x
+
1
)
−
1
=
0
(2)
4
2
(
x
+
)
=
1
3
(3)
10
2
36
(
x
+
)
−
=
0
7
49
(4)
6
2
1
(
x
+
)
=
7
16
(5)
4
2
4
(
x
+
)
−
=
0
3
25
(6)
4
2
1
(
x
−
)
−
=
0
7
4
(7)
2
25
(
x
−
1
)
−
=
0
36
(8)
1
2
25
(
x
+
)
=
2
36
(9)
4
2
1
(
x
+
)
−
=
0
5
4
(10)
2
(
x
+
1
)
=
1
©2025 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
(
x
+
1
)
−
1
=
0
x
+
1
=
±
1
x
=
−
1
±
1
x
=
0
,
−2
(2)
4
2
(
x
+
)
3
=
1
4
x
+
3
=
±
1
x
4
=
−
±
1
3
x
1
7
=
−
,
−
3
3
(3)
10
2
36
(
x
+
)
−
7
49
=
0
10
x
+
7
6
=
±
7
x
10
6
=
−
±
7
7
x
4
16
=
−
,
−
7
7
(4)
6
2
(
x
+
)
7
1
=
16
6
x
+
7
1
=
±
4
x
6
1
=
−
±
7
4
x
17
31
=
−
,
−
28
28
(5)
4
2
4
(
x
+
)
−
3
25
=
0
4
x
+
3
2
=
±
5
x
4
2
=
−
±
3
5
x
14
26
=
−
,
−
15
15
(6)
4
2
1
(
x
−
)
−
7
4
=
0
4
x
−
7
1
=
±
2
x
4
1
=
±
7
2
x
15
1
=
,
14
14
(7)
2
25
(
x
−
1
)
−
36
=
0
x
−
1
5
=
±
6
x
5
=
1
±
6
x
11
1
=
,
6
6
(8)
1
2
(
x
+
)
2
25
=
36
1
x
+
2
5
=
±
6
x
1
5
=
−
±
2
6
x
1
4
=
,
−
3
3
(9)
4
2
1
(
x
+
)
−
5
4
=
0
4
x
+
5
1
=
±
2
x
4
1
=
−
±
5
2
x
3
13
=
−
,
−
10
10
(10)
2
(
x
+
1
)
=
1
x
+
1
=
±
1
x
=
−
1
±
1
x
=
0
,
−2