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©2025 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
2
4
(
x
−
1
)
=
9
(2)
2
1
(
x
+
1
)
−
=
0
2
(3)
2
2
9
(
x
+
)
=
5
4
(4)
3
2
4
(
x
+
)
−
=
0
4
49
(5)
1
2
(
x
+
)
=
1
2
(6)
2
1
(
x
+
1
)
=
9
(7)
1
2
(
x
+
)
=
1
6
(8)
7
2
(
x
+
)
=
1
6
(9)
2
(
x
+
1
)
−
1
=
0
(10)
2
2
1
(
x
+
)
−
=
0
5
3
©2025 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
(
x
−
1
)
4
=
9
x
−
1
2
=
±
3
x
2
=
1
±
3
x
5
1
=
,
3
3
(2)
2
1
(
x
+
1
)
−
2
=
0
x
+
1
2
=
±
2
x
2
=
−
1
±
2
(3)
2
2
(
x
+
)
5
9
=
4
2
x
+
5
3
=
±
2
x
2
3
=
−
±
5
2
x
11
19
=
,
−
10
10
(4)
3
2
4
(
x
+
)
−
4
49
=
0
3
x
+
4
2
=
±
7
x
3
2
=
−
±
4
7
x
13
29
=
−
,
−
28
28
(5)
1
2
(
x
+
)
2
=
1
1
x
+
2
=
±
1
x
1
=
−
±
1
2
x
1
3
=
,
−
2
2
(6)
2
(
x
+
1
)
1
=
9
x
+
1
1
=
±
3
x
1
=
−
1
±
3
x
2
4
=
−
,
−
3
3
(7)
1
2
(
x
+
)
6
=
1
1
x
+
6
=
±
1
x
1
=
−
±
1
6
x
5
7
=
,
−
6
6
(8)
7
2
(
x
+
)
6
=
1
7
x
+
6
=
±
1
x
7
=
−
±
1
6
x
1
13
=
−
,
−
6
6
(9)
2
(
x
+
1
)
−
1
=
0
x
+
1
=
±
1
x
=
−
1
±
1
x
=
0
,
−2
(10)
2
2
1
(
x
+
)
−
5
3
=
0
2
x
+
5
3
=
±
3
x
2
3
=
−
±
5
3