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©2025 数学クラブ http://sugaku.club/
月 日（ ）
● 計算しなさい
[1Q3-20]
(1)
5
7
5
7
125
7
(
＋
)
(2)
2
3
50
3
3
5
(
＋
)
(3)
5
7
20
7
2
7
(
＋
)
(4)
3
5
27
5
3
5
(
＋
)
(5)
20
7
5
7
(
−1
＋
)
(6)
18
7
2
3
50
7
(
＋
)
(7)
3
7
27
7
(
−1
＋
)
(8)
20
7
5
7
5
7
(
＋
)
(9)
3
7
75
7
(
＋
1
)
(10)
5
7
45
7
(
−1
＋
)
©2025 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
5
7
5
7
125
7
(
＋
)
5
7
5
7
5
7
=
(
＋
5
)
5
5
=
＋
5
×
7
7
30
=
7
(2)
2
3
50
3
3
5
(
＋
)
2
3
2
3
3
5
=
(
5
＋
)
2
2
5
=
5
×
＋
3
10
10
=
＋
3
5
(3)
5
7
20
7
2
7
(
＋
)
5
7
5
7
2
7
=
(
2
＋
)
5
1
10
=
2
×
＋
7
7
10
1
10
=
＋
7
7
(4)
3
5
27
5
3
5
(
＋
)
3
5
3
5
3
5
=
(
3
＋
)
3
3
=
3
×
＋
5
5
12
=
5
(5)
20
7
5
7
(
−1
＋
)
5
7
5
7
=
2
(
−1
＋
)
5
7
5
=
−2
＋
2
×
7
2
35
10
=
−
＋
7
7
(6)
18
7
2
3
50
7
(
＋
)
2
7
2
3
2
7
=
3
(
＋
5
)
1
21
2
=
3
×
2
＋
15
×
7
2
21
30
=
＋
7
7
(7)
3
7
27
7
(
−1
＋
)
3
7
3
7
=
(
−1
＋
3
)
3
7
3
=
−
＋
3
×
7
1
21
9
=
−
＋
7
7
(8)
20
7
5
7
5
7
(
＋
)
5
7
5
7
5
7
=
2
(
＋
)
5
5
=
2
×
＋
2
×
7
7
20
=
7
(9)
3
7
75
7
(
＋
1
)
3
7
3
7
=
(
5
＋
1
)
3
3
7
=
5
×
＋
7
15
1
21
=
＋
7
7
(10)
5
7
45
7
(
−1
＋
)
5
7
5
7
=
(
−1
＋
3
)
5
7
5
=
−
＋
3
×
7
1
35
15
=
−
＋
7
7