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©2025 数学クラブ http://sugaku.club/
月 日（ ）
● 有理化しなさい
[1P1-00]
(1)
7
5
(2)
3
13
(3)
17
17
(4)
5
17
(5)
11
13
(6)
3
17
(7)
19
2
(8)
3
19
(9)
7
17
(10)
13
5
(11)
17
2
(12)
7
2
(13)
17
7
(14)
2
5
©2025 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
7
5
7
5
×
35
=
=
5
5
×
5
(2)
3
13
3
13
×
39
=
=
13
13
×
13
(3)
17
17
=
1
(4)
5
17
5
17
×
85
=
=
17
17
×
17
(5)
11
13
11
13
×
143
=
=
13
13
×
13
(6)
3
17
3
17
×
51
=
=
17
17
×
17
(7)
19
2
19
2
×
38
=
=
2
2
×
2
(8)
3
19
3
19
×
57
=
=
19
19
×
19
(9)
7
17
7
17
×
119
=
=
17
17
×
17
(10)
13
5
13
5
×
65
=
=
5
5
×
5
(11)
17
2
17
2
×
34
=
=
2
2
×
2
(12)
7
2
7
2
×
14
=
=
2
2
×
2
(13)
17
7
17
7
×
119
=
=
7
7
×
7
(14)
2
5
2
5
×
10
=
=
5
5
×
5